document.write( "Question 752297: A polynomial functions f has x- intercepts at -5,-3,0,6? Which is a possible equation for the function? \r
\n" );
document.write( "\n" );
document.write( "A. f(x)=(x+5)(x+3)(x-6)
\n" );
document.write( "B. f(x)=x(x+5)(x+3)(x-6)
\n" );
document.write( "C. f(x)=(x-5)(x-3)(x+6)
\n" );
document.write( "D. f(x)=x(x-5)(x-3)(x+6)\r
\n" );
document.write( "\n" );
document.write( "I typed it up exactly how it is on the review. (This is not a question on a test, this is a question on the review for the test. SO I really need to know how to solve this) \n" );
document.write( "
Algebra.Com's Answer #457707 by KMST(5328)![]() ![]() You can put this solution on YOUR website! If the function has x- intercepts at -5, -3, 0, and 6, it means that f(x) is zero for those values of x. \n" ); document.write( "As a consequence, when the function is factored, it must have all of the following factors: \n" ); document.write( "(x-(-5))=(x+5), which becomes zero when x=-5, \n" ); document.write( "(x-(-3))=(x+3), which becomes zero when x=-3, \n" ); document.write( "(x-0)=x, which becomes zero when x=0, and \n" ); document.write( "(x-6), which becomes zero when x=6. \n" ); document.write( "(It could have other factors too, but it must have those four factors). \n" ); document.write( "So |