document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=748512>Question 748512</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Dear Sir/Madam,\r<BR>\n" );
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document.write( "I cannot figure out these simultaneous equations. Please help and show all working out.\r<BR>\n" );
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document.write( "(12-p)/p=12/b<BR>\n" );
document.write( "12/p=(24-b)/b </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #457623 by </B><A HREF=/tutors/aboutme.mpl?userid=malglu><B>malglu(63)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=malglu><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=457623\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> these are proportions so you can multiply the denominators on each side by the numeratpr of the other, to get rid of the fracyions\r<BR>\n" );
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document.write( "you get<BR>\n" );
document.write( "12b -bp =12p<BR>\n" );
document.write( "and<BR>\n" );
document.write( "12b = 24p -pb\r<BR>\n" );
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document.write( "rearrange these so that you have the b term on one side and the other two terms on the other.  then minus one from the other, to get<BR>\n" );
document.write( "24b/36 = p<BR>\n" );
document.write( "i.e. p = 2/3rds b\r<BR>\n" );
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document.write( "if you substuitue this into one of the equations above, for eveyr time you have a 'p' then you will now get an equation which only has b's in it.\r<BR>\n" );
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document.write( "2b^2 -12b = 0\r<BR>\n" );
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document.write( "this can now be solved<BR>\n" );
document.write( "b=0 or b =6 </SPAN>\n" );
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