document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=752189>Question 752189</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The number of solutions for square root of (5x+7) - sq. root of (3x+1) = sq. root of (x+3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #457621 by </B><A HREF=/tutors/aboutme.mpl?userid=malglu><B>malglu(63)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=malglu><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=457621\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> what you need to do is square each side of the equation to get rid of the roots.  you will need to do this twice<BR>\n" );
document.write( "first time<BR>\n" );
document.write( "(sqrt (5x+7) -sqrt (3x+1)) ^2 = sqrt (x+3)^2<BR>\n" );
document.write( "multiply out the brackets to get\r<BR>\n" );
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document.write( "5x+7 -2sqrt (3x+1)(5x+7) + 3x+1 =x+3<BR>\n" );
document.write( "put the sqrt expression on one side of the = sign to get<BR>\n" );
document.write( "7x+5 = 2 sqrt (3x+1)(5x+7)<BR>\n" );
document.write( "now square each side again\r<BR>\n" );
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document.write( "(7x+5) (7x+5) = 2^2 (sqrt (3x+1)^2) (sqrt (5x+7)^2)<BR>\n" );
document.write( "49x^2 +70x +25 = 4 (3x+1) (5x+7)<BR>\n" );
document.write( "11x^2 -38x +3 +0\r<BR>\n" );
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document.write( "use the formula to solve this \r<BR>\n" );
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document.write( "i am in a bit of a rush so cannot check my arithmatic, but the method should be correct.  </SPAN>\n" );
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