document.write( "Question 65247: The perimeter of a triangle is 50 centimeters. Side b is 4 centimeters longer than side a. Side c is 9 centimeters shorter than three times the length os side a. find the length of each side. \n" ); document.write( "
Algebra.Com's Answer #45762 by funmath(2933)\"\" \"About 
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The perimeter of a triangle is 50 centimeters. Side b is 4 centimeters longer than side a. Side c is 9 centimeters shorter than three times the length os side a. find the length of each side.
\n" ); document.write( "Let side a be: a
\n" ); document.write( "Then side b is: a+4
\n" ); document.write( "and side c is: 3a-9
\n" ); document.write( "Perimeter is 50 means that if we add the sides, we get 50.
\n" ); document.write( "Problem to solve:
\n" ); document.write( "(a)+(a+4)+(3a-9)=50
\n" ); document.write( "5a-5=50
\n" ); document.write( "5a-5+5=50+5
\n" ); document.write( "5a=55
\n" ); document.write( "5a/5=55/5
\n" ); document.write( "a=11
\n" ); document.write( "Side a is: a=11 cm
\n" ); document.write( "side b is: a+4=11+4=15 cm
\n" ); document.write( "side c is: 3a-9=3(11)-9=33-9=24 cm
\n" ); document.write( ":
\n" ); document.write( "Sanity check:
\n" ); document.write( " If we add all the sides together, do we get 50 cms?
\n" ); document.write( "11+15+24=50 ?
\n" ); document.write( "50=50
\n" ); document.write( "It appears that we're sane.
\n" ); document.write( "Happy Calculating!!!! \n" ); document.write( "
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