document.write( "Question 752143: 2 log10x+1=log10 250 \n" ); document.write( "
Algebra.Com's Answer #457576 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
\"2+log10%28x%2B1%29=log10+%28250%29\"
\n" ); document.write( "\"+log10%28x%2B1%29%5E2=log10+%28250%29\"
\n" ); document.write( "(x+1)^2=250
\n" ); document.write( "x+1=√250
\n" ); document.write( "x=-1±√250≈1±15.81
\n" ); document.write( "x≈-16.81(reject, (x+1)>0)
\n" ); document.write( "or
\n" ); document.write( "x≈14.81 \n" ); document.write( "
\n" );