document.write( "Question 751928: How to find the x and y intercepts and the vertex of f(x)=2x^2+12x-3 \n" ); document.write( "
Algebra.Com's Answer #457551 by ankor@dixie-net.com(22740)\"\" \"About 
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How to find the x and y intercepts and the vertex of f(x)=2x^2+12x-3
\n" ); document.write( "Write it
\n" ); document.write( "y = 2x^2 + 12x - 3
\n" ); document.write( "The x intercept is when y = 0
\n" ); document.write( "2x^2 + 12x - 3 = 0
\n" ); document.write( "Use the quadratic formula:
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "Where: a=2; b=12; c=-3
\n" ); document.write( "You should get x intercepts of
\n" ); document.write( "x ~ .24
\n" ); document.write( "and
\n" ); document.write( "x ~ -6.24
\n" ); document.write( ":
\n" ); document.write( "The y intercept occurs when x = 0
\n" ); document.write( "y = 2(0^2) + 12(0) - 3
\n" ); document.write( "y = -3 is the y intercept
\n" ); document.write( ":
\n" ); document.write( "Vertex occurs on the axis of symmetry: x = -b/(2a)
\n" ); document.write( "x = \"%28-12%29%2F%282%2A2%29\"
\n" ); document.write( "x = -3 is the axis symmetry
\n" ); document.write( "Find y, when x = -3
\n" ); document.write( "y = 2(-3^2) + 12(-3) - 3
\n" ); document.write( "y = 18 - 36 - 3
\n" ); document.write( "y = -21
\n" ); document.write( ":
\n" ); document.write( "The vertex: -3,-21
\n" ); document.write( " \n" ); document.write( "
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