document.write( "Question 752011: A number is 1 more than twice another. Their squares differ by 176. What are the numbers? \n" ); document.write( "
Algebra.Com's Answer #457521 by tommyt3rd(5050)\"\" \"About 
You can put this solution on YOUR website!
We'll call them x and y\r
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\n" ); document.write( "\n" ); document.write( "\"y=2x%2B1\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-y%5E2=176\"\r
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\n" ); document.write( "\n" ); document.write( "then\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-%282x%2B1%29%5E2=176\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-%284x%5E2%2B4x%2B1%29=176\"\r
\n" ); document.write( "\n" ); document.write( "\"-3x%5E2-4x-177=0\"\r
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"3x%5E2%2B4x%2B177+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%284%29%5E2-4%2A3%2A177=-2108\".
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\n" ); document.write( " The discriminant -2108 is less than zero. That means that there are no solutions among real numbers.

\n" ); document.write( " If you are a student of advanced school algebra and are aware about imaginary numbers, read on.

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\n" ); document.write( " In the field of imaginary numbers, the square root of -2108 is + or - \"sqrt%28+2108%29+=+45.912961132996\".
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\n" ); document.write( " The solution is
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\n" ); document.write( " Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+3%2Ax%5E2%2B4%2Ax%2B177+%29\"

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\n" ); document.write( "\n" ); document.write( "so we see that no pair of real numbers wtii work but\r
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\n" ); document.write( "\n" ); document.write( "\"%0D%0A%281%2F3%29%2A%28-2+%2B-+i+%2Asqrt%28527%29%29%0D%0A\"\r
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\n" ); document.write( "\n" ); document.write( "does work\r
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\n" ); document.write( "\n" ); document.write( ":)
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