document.write( "Question 752003: For questions 3-5, find the first 4 terms and the 8th term of the recursively-defined sequence.\r
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document.write( "3. b1 = 2 and bk+1 = 3bk, for k>0\r
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document.write( "4. v1 = 0.75 and vn = (-2)vk-1 for n>1\r
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document.write( "5. c1 = 2, c2 = -1, and ck+2 = ck + ck+1 for k>0\r
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Algebra.Com's Answer #457508 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! find the first 4 terms and the 8th term of the recursively-defined sequence. \n" ); document.write( "3. b1 = 2 and bk+1 = 3bk, for k>0 \n" ); document.write( "b(1) = 2 \n" ); document.write( "b(2) = 3*b1 = 3*2 = 6 \n" ); document.write( "b(3) = 3*b2 = 3*6 = 3^2*2 = 9*2 = 18 \n" ); document.write( "b(4) = 3*b3 = 3*3^2*2 = 3^3*2 = 54 \n" ); document.write( "---- \n" ); document.write( "b(8) = 3^4*2 = 81*2 = 162 \n" ); document.write( "===================================================== \r \n" ); document.write( "\n" ); document.write( "4. v1 = 0.75 and vn = (-2)vk-1 for n>1 \n" ); document.write( "v(1) = 3/4 \n" ); document.write( "v(2) = -2(3/4) \n" ); document.write( "v(3) = (-2)^2(3/4) = 3 \n" ); document.write( "v(4) = (-2)^3(3/4) = -6 \n" ); document.write( "---- \n" ); document.write( "v(8) = (-2)^6(3/4) = 48 \n" ); document.write( "============================ \r \n" ); document.write( "\n" ); document.write( "5. c1 = 2, c2 = -1, and ck+2 = ck + ck+1 for k>0 \n" ); document.write( "c(1) = 2 \n" ); document.write( "c(2) = -1 \n" ); document.write( "c(3) = 2+-1 = 1 \n" ); document.write( "c(4) = -1 + 1 = 0 \n" ); document.write( "---- \n" ); document.write( "c(8) = c(6) + c(5) = [c(4)+c(5)] + c(5) = [0+1+1] = 2 \n" ); document.write( "=================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================= \n" ); document.write( " \n" ); document.write( " |