document.write( "Question 751986: Im doing Elimination using Multiplication. The problem is 1/4x + 4y = 2 3/4 and 3x + 1/2y = 9 1/4 \n" ); document.write( "
Algebra.Com's Answer #457502 by josgarithmetic(39838)\"\" \"About 
You can put this solution on YOUR website!
\"1%2F4x+%2B+4y+=+2%26+3%2F4\" and \"3x+%2B+1%2F2y+=+9%26+1%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "Did you really mean this:
\n" ); document.write( "\"%281%2F4%29x+%2B+4y+=+2%26+3%2F4\" and \"3x+%2B+%281%2F2%29y+=+9%26+1%2F4\"
\n" ); document.write( "?\r
\n" ); document.write( "\n" ); document.write( "Multiply either equation by some number so that the coefficients on either the x or the y are the same, and then subtract one equation from the other equation and solve for the single variable present. \r
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\n" ); document.write( "\n" ); document.write( "Alternatively multiply EACH equation by numbers to make the coefficient on either x or y match; and then subtract one equation from the other. Solve the variable.\r
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\n" ); document.write( "\n" ); document.write( "Here is one way:
\n" ); document.write( "Starting with your second equation,
\n" ); document.write( "\"8%2A%283x+%2B+%281%2F2%29y%29+=+8%2A%289%26+1%2F4%29\"
\n" ); document.write( "Gives you
\n" ); document.write( "\"24x%2B4y=74\" another equivalent equation to your second equation.\r
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\n" ); document.write( "\n" ); document.write( "So your system could be
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\n" ); document.write( "\"%281%2F4%29x+%2B+4y+=+2%26+3%2F4\"
\n" ); document.write( "\"24x%2B4y=74\"
\n" ); document.write( "-----------------------------\r
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\n" ); document.write( "\n" ); document.write( "See that the coefficients on y in both these are both 4.
\n" ); document.write( "Now, subtract the first equation from the second equation, and solve for x.
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