document.write( "Question 751914: What are the center and radius of the circle whose equation is x2 + (y-3)2 = 144? \n" ); document.write( "
Algebra.Com's Answer #457461 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! x^2 + (y - 3)^2 = 144 \n" ); document.write( "Multiply out the bracket. \n" ); document.write( "x^2 +(y^2 - 6y + 9) = 144 \n" ); document.write( "x^2 + y^2 - 6y + 9 - 144 = 0 \n" ); document.write( "x^2 + y^2 -6y - 135 = 0\r \n" ); document.write( "\n" ); document.write( "Centre (0, 3) radius =sqrrt 0^2 + 3^2 + 135 \n" ); document.write( " = sqrrt 144 \n" ); document.write( " = 12\r \n" ); document.write( "\n" ); document.write( "Hope this helps. \n" ); document.write( ":-) \n" ); document.write( " |