document.write( "Question 751914: What are the center and radius of the circle whose equation is x2 + (y-3)2 = 144? \n" ); document.write( "
Algebra.Com's Answer #457461 by Cromlix(4381)\"\" \"About 
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x^2 + (y - 3)^2 = 144
\n" ); document.write( "Multiply out the bracket.
\n" ); document.write( "x^2 +(y^2 - 6y + 9) = 144
\n" ); document.write( "x^2 + y^2 - 6y + 9 - 144 = 0
\n" ); document.write( "x^2 + y^2 -6y - 135 = 0\r
\n" ); document.write( "\n" ); document.write( "Centre (0, 3) radius =sqrrt 0^2 + 3^2 + 135
\n" ); document.write( " = sqrrt 144
\n" ); document.write( " = 12\r
\n" ); document.write( "\n" ); document.write( "Hope this helps.
\n" ); document.write( ":-)
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