document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=751866>Question 751866</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A bank teller notices that he has 50 coins all of which are 5c and 10c pieces. He finds that the value of the coins is $4.20. How many of each must he have?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #457444 by </B><A HREF=/tutors/aboutme.mpl?userid=malglu><B>malglu(63)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=malglu><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=457444\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> there are 50 coins altogether<BR>\n" );
document.write( "let n = the amount of 5c pieces and d the 10c pieces<BR>\n" );
document.write( "so n+d =50<BR>\n" );
document.write( "rearranging<BR>\n" );
document.write( "d=50-n\r<BR>\n" );
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document.write( "now the value of n = 5 (cents), and d =10 (cents)<BR>\n" );
document.write( "so 5n +10d = 420 (cents)\r<BR>\n" );
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document.write( "substituting d=50-n instead of d in the equation<BR>\n" );
document.write( "5n + 10 (50-n) = 420<BR>\n" );
document.write( "multiplying out and rearranging you get <BR>\n" );
document.write( "80/5 =n<BR>\n" );
document.write( "so n = 16<BR>\n" );
document.write( "therefore d = 34<BR>\n" );
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