document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=751859>Question 751859</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3 ( log 5 - log 3 ) - ( log 5 - 2 log 6 ) = 2 - log n , find n.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #457431 by </B><A HREF=/tutors/aboutme.mpl?userid=dkppathak><B>dkppathak(439)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dkppathak><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=dkppathak><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=457431\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3 ( log 5 - log 3 ) - ( log 5 - 2 log 6 ) = 2 - log n , find n.<BR>\n" );
document.write( "3log 5/3 -lg5/36 + log n =2<BR>\n" );
document.write( "log 125/27 -log 5/36 +log n =log100<BR>\n" );
document.write( "log 125x36/5x27 +log n =log100<BR>\n" );
document.write( "log 100/3  +log n =log100<BR>\n" );
document.write( "log100n/3=log100<BR>\n" );
document.write( "100n/3=100<BR>\n" );
document.write( "n=100x3/100 =3<BR>\n" );
document.write( "ANSWER N = 3<BR>\n" );
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