document.write( "Question 751662: Can you help me with this word problem? A mechanic has 30 pints of an antifreeze-and-water solution that is 80% antifreeze. How any pints of water should be added to make a solution that is 60% antifreeze? \n" ); document.write( "
Algebra.Com's Answer #457357 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"+.8%2A30+=+24+\" pints of antifreeze in 80% solution
\n" ); document.write( "Let \"+w+\" = pints of water to be added
\n" ); document.write( "to make solution 60% antifreeze
\n" ); document.write( "---------------
\n" ); document.write( "\"+24+%2F+%28+30+%2B+w+%29+=+.6+\"
\n" ); document.write( "\"+24+=+.6%2A%28+30+%2B+w+%29+\"
\n" ); document.write( "\"+24+=+18+%2B+.6w+\"
\n" ); document.write( "\"+.6w+=+6+\"
\n" ); document.write( "\"+w+=+10+\"
\n" ); document.write( "10 pints of waters needs to be added
\n" ); document.write( "check:
\n" ); document.write( "\"+24+%2F+%28+30+%2B+w+%29+=+.6+\"
\n" ); document.write( "\"+24+%2F+%28+30+%2B+10+%29+=+.6+\"
\n" ); document.write( "\"+24+%2F+40+=+.6+\"
\n" ); document.write( "\"+24+=+.6%2A40+\"
\n" ); document.write( "\"+24+=+24+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );