document.write( "Question 751654: Two cards are chosen at random without replacement from a deck of 52 cards containing 4 kings. Which expression could be used to find the probability of choosing two kings? \n" ); document.write( "
Algebra.Com's Answer #457335 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For the first card drawn, there are 4 ways out of 52 to get a king, or 1/13. Then, given that a king was drawn on the first draw, you have 3 kings left in the deck, but the deck now only has 51 cards, so 3/51 = 1/17, and these are independent events, so the product of the two probabilities. I can't tell you \"which\" expression because YOU were too lazy to share the choices with us -- you will have to calculate which of your choices is equivalent to 1/13 times 1/17\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "Egw to Beta kai to Sigma \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |