document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=751612>Question 751612</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is 4 greater than another number. When three times the smaller number is added to twice the larger one, the result in 43. Find the numbers.\r<BR>\n" );
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document.write( "What is the formula for this question?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #457303 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=457303\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One number is 4 greater than another number. When three times the smaller number is added to twice the larger one, the result in 43. Find the numbers. <BR>\n" );
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document.write( "If x = y + 5, y must be the smaller number.<BR>\n" );
document.write( "3y + 2x = 43<BR>\n" );
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document.write( "Substitute for \"x\" and solve for \"y\":<BR>\n" );
document.write( "3y + 2(y+5) = 43<BR>\n" );
document.write( "3y + 2y + 10 = 43<BR>\n" );
document.write( "5y = 33<BR>\n" );
document.write( "y = 33/6<BR>\n" );
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document.write( "Solve for \"x\":<BR>\n" );
document.write( "x = y + 5<BR>\n" );
document.write( "x = (33/6) + (30/6)<BR>\n" );
document.write( "x = 63/6<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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