document.write( "Question 751535: \"+y=%7Cx-1%7C%2B2\" \n" ); document.write( "
Algebra.Com's Answer #457291 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
Instead of this result, \"+y=%7Cx-1%7C%2B2\", use the absolute value portion of function as abs() and then put the tags around the whole function equation:\r
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\n" ); document.write( "\n" ); document.write( "y=abs(x-1)+2, and with the triple braces,
\n" ); document.write( "\"y=abs%28x-1%29%2B2\".\r
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\n" ); document.write( "\n" ); document.write( "Critical point is at \"x=1\".
\n" ); document.write( "at \"x%3C1\", \"x-1%3C0\" and \"y=1-x%2B2\" or \"y=-x%2B3\".\r
\n" ); document.write( "\n" ); document.write( "At \"x%3E=1\", \"y=x-1%2B2\", or \"y=x%2B1\".\r
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\n" ); document.write( "\n" ); document.write( "SUMMARY:
\n" ); document.write( "You will graph for \"x%3C1\", \"y=-x%2B3\"
\n" ); document.write( "and for \"x%3E=1\", \"y=x%2B1\"
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