document.write( "Question 751575: a farmer has 34m of fencing. he wants to pen in some animals. what is the maximum area he can enclose with this length of fencing, using a regular quadrilateral pen? \n" ); document.write( "
Algebra.Com's Answer #457282 by Cromlix(4381)\"\" \"About 
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Perimeter = 2 lengths + 2 widths
\n" ); document.write( " 2l + 2w = 34m
\n" ); document.write( " Therefore 2l = 34 - 2w
\n" ); document.write( " l = 17 - w\r
\n" ); document.write( "\n" ); document.write( " Area = length x width
\n" ); document.write( " ( 17 - w) x w
\n" ); document.write( " 17w - w^2\r
\n" ); document.write( "\n" ); document.write( " Differentiate\r
\n" ); document.write( "\n" ); document.write( " 17 - 2w
\n" ); document.write( " 17 - 2w = 0
\n" ); document.write( " - 2w = - 17
\n" ); document.write( " w = 8.5\r
\n" ); document.write( "\n" ); document.write( " By inserting values below and above 8.5 into 17 - 2w
\n" ); document.write( " the value 8.5 is found to be a maximum.\r
\n" ); document.write( "\n" ); document.write( " length = 8.5
\n" ); document.write( " width = 8.5\r
\n" ); document.write( "\n" ); document.write( " Max area = 72.25 m^2
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