document.write( "Question 751485: given: point Q(-2,3) midpoint M(-3,-1) point P(x,y)\r
\n" ); document.write( "\n" ); document.write( "Find coordinates of the point P using a formula, check with graph and then find y-coordinates equal to 1 that are a distance of sqrt 6 from the point Q
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Algebra.Com's Answer #457233 by stanbon(75887)\"\" \"About 
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given: point Q(-2,3) midpoint M(-3,-1) point P(x,y)
\n" ); document.write( "Find coordinates of the point P using a formula
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\n" ); document.write( "(x+-2)/2 = -3
\n" ); document.write( "x-2 = -6
\n" ); document.write( "x = -4
\n" ); document.write( "-----
\n" ); document.write( "(y+3)/2 = -1
\n" ); document.write( "y+3 = -2
\n" ); document.write( "y = -5
\n" ); document.write( "---
\n" ); document.write( "P(x,y) = P(-4,-5)
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\n" ); document.write( "check with graph
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\n" ); document.write( "find y-coordinates equal to 1 that are a distance of sqrt 6
\n" ); document.write( "from the point Q(-2,3)
\n" ); document.write( "---
\n" ); document.write( "Find \"x\" where (x,1) are at distance sqrt(6) from Q(-2,3)
\n" ); document.write( "sqrt[(x+2)^2 + (1-3)^2] = sqrt(6)
\n" ); document.write( "(x+2)^2 + 4 = 6
\n" ); document.write( "(x+2)^2 = 2
\n" ); document.write( "x+2 = sqrt(2) or x+2 = -sqrt(2)
\n" ); document.write( "x = -2+sqrt(2) or x = -2-sqrt(2)
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\n" ); document.write( "cheers,
\n" ); document.write( "Stan H.
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