document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=751439>Question 751439</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose you have a bag containing the following <BR>\n" );
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document.write( "18 white beads<BR>\n" );
document.write( "12 black beads <BR>\n" );
document.write( "24 yellow beads <BR>\n" );
document.write( "8 pink beads..\r<BR>\n" );
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document.write( "Suppose you draw 2 beads out of the bag with replacement. Find the probability of drawing a red bead and then a black bead..<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #457197 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=457197\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are 32+18+12+24+8 = 94 beads total\r<BR>\n" );
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document.write( "P(red then black) = P(red) * P(black)\r<BR>\n" );
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document.write( "P(red then black) = (32/94)*(12/94)\r<BR>\n" );
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document.write( "P(red then black) = (32*12)/(94*94)\r<BR>\n" );
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document.write( "P(red then black) = (384)/(8836)\r<BR>\n" );
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document.write( "P(red then black) = 96/2209\r<BR>\n" );
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document.write( "P(red then black) = 0.04345857854232  (note: this is approximate) </SPAN>\n" );
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