document.write( "Question 751433: an arrow is shot into the air from a building that is 32ft high. the height of the arrow after t seconds is given by the formula h(t)=-16t^2+48t+32=0
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Algebra.Com's Answer #457195 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Solve \"-16t%5E2%2B48t%2B32=0\" for t\r
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\n" ); document.write( "\n" ); document.write( "Use the quadratic formula to solve for t\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-%2848%29%2B-sqrt%28%2848%29%5E2-4%28-16%29%2832%29%29%29%2F%282%28-16%29%29\" Plug in \"a+=+-16\", \"b+=+48\", \"c+=+32\"\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-48%2B-sqrt%282304-%28-2048%29%29%29%2F%28-32%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-48%2B-sqrt%282304%2B2048%29%29%2F%28-32%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-48%2B-sqrt%284352%29%29%2F%28-32%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-48%2Bsqrt%284352%29%29%2F%28-32%29\" or \"t+=+%28-48-sqrt%284352%29%29%2F%28-32%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-48%2B16%2Asqrt%2817%29%29%2F%28-32%29\" or \"t+=+%28-48-16%2Asqrt%2817%29%29%2F%28-32%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%283-sqrt%2817%29%29%2F2\" or \"t+=+%283%2Bsqrt%2817%29%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+-0.561553\" or \"t+=+3.561553\"\r
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\n" ); document.write( "\n" ); document.write( "Ignore the negative solution (since a negative time doesn't make sense)\r
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\n" ); document.write( "\n" ); document.write( "So the only solution is approximately \"t+=+3.561553\"\r
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\n" ); document.write( "\n" ); document.write( "This means it will take approximately 3.561553 seconds for it to hit the ground.
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