document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=750525>Question 750525</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a right triangle, a and b are the lengths of the legs and c is the length of the hypotenuse. If a = 70 millimeters and b = 24 millimeters, what is the perimeter? If necessary, round to the nearest tenth.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #457083 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=457083\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Pythagoras.<BR>\n" );
document.write( "a^2 + b^2 = c^2<BR>\n" );
document.write( "70^2 + 24^2 = c^2<BR>\n" );
document.write( "      c^2 = 5476<BR>\n" );
document.write( "        c = 74 mm<BR>\n" );
document.write( "Therefore perimeter <BR>\n" );
document.write( "= 70 + 24 + 74 = 168 mm<BR>\n" );
document.write( "Hope this helps<BR>\n" );
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