document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=65188>Question 65188</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello I have done 7 out of 10 problems these are giving me some problems. \r<BR>\n" );
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document.write( "1 A right tringle has sides of 20cm and 15 cm. What is the length of the hypothenus. Thanks \r<BR>\n" );
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document.write( "6 Simply 2(sqrt12)/4(sqrt27). Thanks \r<BR>\n" );
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document.write( "10 Find the distance between (4,0 and (-9,0)\r<BR>\n" );
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document.write( "Thanks for your help and have a happy Holiday. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #45708 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=45708\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 11. Find the length of the hypotenuse if the two legs are 20cm and 15cm.<BR>\n" );
document.write( "Remember that in a right triangle, the lengths of the sides are in proprtion to: 3, 4, and 5, and the hypotenuse is always the longest side.\r<BR>\n" );
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document.write( "So:<BR>\n" );
document.write( "15 = 3*5<BR>\n" );
document.write( "20 = 4*5<BR>\n" );
document.write( "x = 5*5 = 25\r<BR>\n" );
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document.write( "The hypotenuse is 25cm.\r<BR>\n" );
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document.write( "6. Simplify:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2sqrt%2812%29%2F4sqrt%2827%29 ALIGN=MIDDLE  ALT=\"2sqrt%2812%29%2F4sqrt%2827%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Cancel 2 in the top and bottom.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2812%29%2F2sqrt%2827%29 ALIGN=MIDDLE  ALT=\"sqrt%2812%29%2F2sqrt%2827%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Simplify the square roots.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%283%2A4%29%2F2sqrt%283%2A9%29 ALIGN=MIDDLE  ALT=\"sqrt%283%2A4%29%2F2sqrt%283%2A9%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2sqrt%283%29%2F3%2A2sqrt%283%29 ALIGN=MIDDLE  ALT=\"2sqrt%283%29%2F3%2A2sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Cancel where appropriate.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F3 ALIGN=MIDDLE  ALT=\"1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "10. The distance between two points, (x1, y1) and (x2, y2) is given by:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d+=+sqrt%28%28x2-x1%29%5E2+%2B+%28y2-y1%29%5E2%29 ALIGN=MIDDLE  ALT=\"d+=+sqrt%28%28x2-x1%29%5E2+%2B+%28y2-y1%29%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Applying this to your two points:(4, 0) and (-9, 0)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d+=+sqrt%28%28-9-4%29%5E2+%2B+%280-0%29%5E2%29 ALIGN=MIDDLE  ALT=\"d+=+sqrt%28%28-9-4%29%5E2+%2B+%280-0%29%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d+=+sqrt%28%28-13%29%5E2%29 ALIGN=MIDDLE  ALT=\"d+=+sqrt%28%28-13%29%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d+=+sqrt%28169%29 ALIGN=MIDDLE  ALT=\"d+=+sqrt%28169%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d+=+13 ALIGN=MIDDLE  ALT=\"d+=+13\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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