document.write( "Question 751108: Classify the conic section:\r
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\n" ); document.write( "\n" ); document.write( "6. What is the standard equation of the circle with radius 4, and center (0,0)?\r
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\n" ); document.write( "\n" ); document.write( "12. What is the center of the ellipse whose equation is (x+1)2 / 4 + (y2)/1 = 1?\r
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\n" ); document.write( "\n" ); document.write( "15. What is the center of the hyperbola whose equation is [(x+2)2 / 9] - [(y-2)2 / 16] = 1?\r
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\n" ); document.write( "\n" ); document.write( "16. How does the graph of the hyperbola whose equation is (x2)/9 - (y2)/25 = 1 open?\r
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Algebra.Com's Answer #457063 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Classify the conic section:\r\n" );
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document.write( "1. x² + y² = 36  <-- circle since x² and y² have the SAME COEFFICIENT, 1,\r\n" );
document.write( "                     when on the same side of the equation.      \r\n" );
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document.write( "2. x² - y² = 36  <-- hyperbola since x² and y² have coefficients with\r\n" );
document.write( "                     OPPOSITE SIGNS when on the same side of the equation.\r\n" );
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document.write( "3. 5x² + 9y² = 45 <-- ellipse since x² and y² have different coefficients \r\n" );
document.write( "                      with THE SAME SIGN when on the same side of the \r\n" );
document.write( "                      equation.\r\n" );
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document.write( " 4. x² + y² = 121  <-- circle since x² and y² have the SAME COEFFICIENT, 1,\r\n" );
document.write( "                       when on the same side of the equation.  \r\n" );
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document.write( " 5. y = 17         <-- line because it has NO x² or y² terms.\r\n" );
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document.write( "6. What is the standard equation of the circle with radius 4, and center (0,0)?\r\n" );
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document.write( "Start woth \r\n" );
document.write( "   \r\n" );
document.write( "   (x-h)²+(y-k)²=r² where (h,k) is the center and r is the radius\r\n" );
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document.write( "   (x-0)²+(y-0)²=4²\r\n" );
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document.write( "   x² + y² = 16\r\n" );
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document.write( "7. What is the standard equation of the circle with radius 5, and center (-5,-1)?\r\n" );
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document.write( "Start woth \r\n" );
document.write( "   \r\n" );
document.write( "   (x-h)²+(y-k)²=r² where (h,k) is the center and r is the radius\r\n" );
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document.write( "   (x-(-5))²+(y-(-1))²=5²\r\n" );
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document.write( "     (x+5)² + (y+1)² = 25\r\n" );
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document.write( "8. Name the center and radius of the circle whose equation is x² + y² = 49.\r\n" );
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document.write( "   The reverse of the other problems:\r\n" );
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document.write( "   Write it as\r\n" );
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document.write( "   (x-0)²+(y-0)²=7²\r\n" );
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document.write( "   Compare that to\r\n" );
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document.write( "   (x-h)²+(y-k)²=r²\r\n" );
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document.write( "   So the center is (h,k) = (0,0,) and its radius is 7 \r\n" );
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document.write( "9. What are the vertices of the ellipse whose equation is (x²)/25 + (y²)/9 = 1?\r\n" );
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document.write( "   The ellipse that has equation \r\n" );
document.write( "\r\n" );
document.write( "   \"%28x-h%29%5E2%2Fa%5E2\"\"%22%22%2B%22%22\"\"%28y-k%29%5E2%2Fb%5E2\"\"%22%22=%22%22\"\"%22%221%22%22\"\r\n" );
document.write( "\r\n" );
document.write( "   Since a > b, and a is uder x, the ellipse looks like this \"drawing%2820%2C10%2C-2%2C2%2C-1%2C1%2Carc%280%2C0%2C-3.9%2C1.9%29+%29\"\r\n" );
document.write( "\r\n" );
document.write( "   has vertices (h+a,k) and (h-a,k).  The center is (h,k)\r\n" );
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document.write( "   Write your equation as\r\n" );
document.write( "\r\n" );
document.write( "   \"%28x-0%29%5E2%2F5%5E2\"\"%22%22%2B%22%22\"\"%28y-0%29%5E2%2F3%5E2\"\"%22%22=%22%22\"\"%22%221%22%22\"\r\n" );
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document.write( "   Then the vertices are (h+a,k) and (h-a,k) which are\r\n" );
document.write( "                         (0+5,0) and (0-5,0)\r\n" );
document.write( "                           (5,0) and (-5,0)\r\n" );
document.write( "          \r\n" );
document.write( "\r\n" );
document.write( "10. What are the vertices of the ellipse whose equation is (x²)/9 + (y²)/36 = 1?\r\n" );
document.write( "\r\n" );
document.write( "   The ellipse that has equation \r\n" );
document.write( "\r\n" );
document.write( "   \"%28x-h%29%5E2%2Fb%5E2\"\"%22%22%2B%22%22\"\"%28y-k%29%5E2%2Fa%5E2\"\"%22%22=%22%22\"\"%22%221%22%22\"\r\n" );
document.write( "\r\n" );
document.write( "   Since a > b, and a is under y, the ellipse looks like this \"drawing%2810%2C20%2C-1%2C1%2C-2%2C2%2Carc%280%2C0%2C1.9%2C-3.9%29+%29\" \r\n" );
document.write( "   \r\n" );
document.write( "has vertices (h,k+a) and (h,k-a).  The center is (h,k)\r\n" );
document.write( "\r\n" );
document.write( "   Write your equation as\r\n" );
document.write( "\r\n" );
document.write( "   \"%28x-0%29%5E2%2F3%5E2\"\"%22%22%2B%22%22\"\"%28y-0%29%5E2%2F6%5E2\"\"%22%22=%22%22\"\"%22%221%22%22\"\r\n" );
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document.write( "   Then the vertices are (h,k+a) and (h,k-a) which are\r\n" );
document.write( "                         (0,0+6) and (0,0-6)\r\n" );
document.write( "                          (0,-6) and (0,6)\r\n" );
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document.write( "11. What is the center of the ellipse whose equation is (x²)/25 + (y²)/4 = 1?\r\n" );
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document.write( "    Write it as\r\n" );
document.write( "\r\n" );
document.write( "     \"%28x-0%29%5E2%2F5%5E2\"\"%22%22%2B%22%22\"\"%28y-0%29%5E2%2F2%5E2\"\"%22%22=%22%22\"\"%22%221%22%22\"\r\n" );
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document.write( "     compare to\r\n" );
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document.write( "     \"%28x-h%29%5E2%2Fa%5E2\"\"%22%22%2B%22%22\"\"%28y-k%29%5E2%2Fb%5E2\"\"%22%22=%22%22\"\"%22%221%22%22\"\r\n" );
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document.write( "     So center = (h,k) = (0,0) \r\n" );
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document.write( "\r\n" );
document.write( "12. What is the center of the ellipse whose equation is (x+1)²/4 + (y²)/1 = 1?\r\n" );
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document.write( " \r\n" );
document.write( "   The ellipse that has equation \r\n" );
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document.write( "   \"%28x-h%29%5E2%2Fa%5E2\"\"%22%22%2B%22%22\"\"%28y-k%29%5E2%2Fb%5E2\"\"%22%22=%22%22\"\"%22%221%22%22\"\r\n" );
document.write( "\r\n" );
document.write( "   Since a > b, and a is under x, the ellipse looks like this \"drawing%2820%2C10%2C-2%2C2%2C-1%2C1%2Carc%280%2C0%2C-3.9%2C1.9%29+%29\"\r\n" );
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document.write( "   It has center is (h,k)\r\n" );
document.write( "\r\n" );
document.write( "   Write your equation as\r\n" );
document.write( "\r\n" );
document.write( "   \"%28x%2B1%29%5E2%2F2%5E2\"\"%22%22%2B%22%22\"\"%28y-0%29%5E2%2F1%5E2\"\"%22%22=%22%22\"\"%22%221%22%22\"\r\n" );
document.write( "\r\n" );
document.write( "   Compare it to\r\n" );
document.write( "\r\n" );
document.write( "   \"%28x-h%29%5E2%2Fa%5E2\"\"%22%22%2B%22%22\"\"%28y-k%29%5E2%2Fb%5E2\"\"%22%22=%22%22\"\"%22%221%22%22\"\r\n" );
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document.write( "   and see x+1 = x-h   and   y-k = y-0\r\n" );
document.write( "             1 = -h           -k = 0\r\n" );
document.write( "            -1 = h             k = 0\r\n" );
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document.write( "   So the center = (h,k) = (-1,0)\r\n" );
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document.write( "13. What is the center of the hyperbola whose equation is (x²) - (y²) = 1?\r\n" );
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document.write( "   The hyperbola that has equation \r\n" );
document.write( "\r\n" );
document.write( "   \"%28x-h%29%5E2%2Fa%5E2\"\"%22%22-%22%22\"\"%28y-k%29%5E2%2Fb%5E2\"\"%22%22=%22%22\"\"%22%221%22%22\"\r\n" );
document.write( "\r\n" );
document.write( "   Since a is uder x, the hyperbola looks like this )(\r\n" );
document.write( "\r\n" );
document.write( "   It has has center is (h,k)\r\n" );
document.write( "\r\n" );
document.write( "   Write your equation as\r\n" );
document.write( "\r\n" );
document.write( "   \"%28x-0%29%5E2%2F1%5E2\"\"%22%22%2B%22%22\"\"%28y-0%29%5E2%29%2F1%5E2\"\"%22%22=%22%22\"\"%22%221%22%22\"\r\n" );
document.write( "\r\n" );
document.write( "   Compare to\r\n" );
document.write( "\r\n" );
document.write( "   \"%28x-h%29%5E2%29%2Fa%5E2\"\"%22%22-%22%22\"\"%28y-k%29%5E2%29%2Fb%5E2\"\"%22%22=%22%22\"\"%22%221%22%22\"\r\n" );
document.write( "\r\n" );
document.write( "   and h=0, k=0, so its center is (h,k) = (0,0) \r\n" );
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document.write( "\r\n" );
document.write( "14. What is the center of the hyperbola whose equation is (x²)/4 - (y²)/9 = 1?\r\n" );
document.write( "\r\n" );
document.write( "   The hyperbola that has equation \r\n" );
document.write( "\r\n" );
document.write( "   \"%28x-h%29%5E2%29%2Fa%5E2\"\"%22%22-%22%22\"\"%28y-k%29%5E2%29%2Fb%5E2\"\"%22%22=%22%22\"\"%22%221%22%22\"\r\n" );
document.write( "\r\n" );
document.write( "   Since a is uder x, the hyperbola looks like this )(\r\n" );
document.write( "   It has has center is (h,k)\r\n" );
document.write( "\r\n" );
document.write( "   Write your equation as\r\n" );
document.write( "\r\n" );
document.write( "   \"%28x-0%29%5E2%29%2F2%5E2\"\"%22%22%2B%22%22\"\"%28y-0%29%5E2%29%2F3%5E2\"\"%22%22=%22%22\"\"%22%221%22%22\"\r\n" );
document.write( "\r\n" );
document.write( "   Compare to\r\n" );
document.write( "\r\n" );
document.write( "   \"%28x-h%29%5E2%29%2Fa%5E2\"\"%22%22-%22%22\"\"%28y-k%29%5E2%29%2Fb%5E2\"\"%22%22=%22%22\"\"%22%221%22%22\"\r\n" );
document.write( "\r\n" );
document.write( "   and h=0, k=0, so its center is (h,k) = (0,0)\r\n" );
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document.write( " \r\n" );
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document.write( "15. What is the center of the hyperbola whose equation is [(x+2)²/9] - [(y-2)²/16] = 1?\r\n" );
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document.write( "   The hyperbola that has equation \r\n" );
document.write( "\r\n" );
document.write( "   \"%28x-h%29%5E2%2Fa%5E2\"\"%22%22-%22%22\"\"%28y-k%29%5E2%2Fb%5E2\"\"%22%22=%22%22\"\"%22%221%22%22\"\r\n" );
document.write( "\r\n" );
document.write( "   Since a is under x, the hyperbola looks like this )(\r\n" );
document.write( "   It has has center is (h,k)\r\n" );
document.write( "\r\n" );
document.write( "   Write your equation as\r\n" );
document.write( "\r\n" );
document.write( "   \"%28x%2B2%29%5E2%2F3%5E2\"\"%22%22-%22%22\"\"%28y-2%29%5E2%2F4%5E2\"\"%22%22=%22%22\"\"%22%221%22%22\"\r\n" );
document.write( "\r\n" );
document.write( "   Compare to\r\n" );
document.write( "\r\n" );
document.write( "   \"%28x-h%29%5E2%2Fa%5E2\"\"%22%22-%22%22\"\"%28y-k%29%5E2%2Fb%5E2\"\"%22%22=%22%22\"\"%22%221%22%22\"\r\n" );
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document.write( "   x-h = x+2       y-k = y-2\r\n" );
document.write( "    -h = 2          -k = -2\r\n" );
document.write( "     h = -2          k = 2\r\n" );
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document.write( "     So the center is (h,k) = (-2,2)\r\n" );
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document.write( " 16. How does the graph of the hyperbola whose equation is (x²)/9 - (y²)/25 = 1 open?\r\n" );
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document.write( "   The hyperbola that has equation \r\n" );
document.write( "\r\n" );
document.write( "   \"%28x-h%29%5E2%2Fa%5E2\"\"%22%22-%22%22\"\"%28y-k%29%5E2%2Fb%5E2\"\"%22%22=%22%22\"\"%22%221%22%22\"\r\n" );
document.write( "\r\n" );
document.write( "   Since a is under x, the hyperbola looks like this )(,\r\n" );
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document.write( "   so it opens right and left\r\n" );
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document.write( "17. How does the graph of the hyperbola whose equation is (y²)/4 - (x²)/9 = 1\r\n" );
document.write( " open?\r\n" );
document.write( "\r\n" );
document.write( "   The hyperbola that has equation \r\n" );
document.write( "\r\n" );
document.write( "   \"%28y-k%29%5E2%2Fa%5E2\"\"%22%22-%22%22\"\"%28x-h%29%5E2%2Fb%5E2\"\"%22%22=%22%22\"\"%22%221%22%22\"\r\n" );
document.write( "\r\n" );
document.write( "   Since a is under y, the hyperbola looks like this \r\n" );
document.write( "   so it opens up and down.\r\n" );
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document.write( " 18. Classify the conic section of the equation x² + 2x + y² + 6y = 15.\r\n" );
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document.write( "Circle since x² and y² have the SAME COEFFICIENT, 1, when on the same \r\n" );
document.write( "side of the equation.\r\n" );
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document.write( " 19. Classify the conic section of the equation 4x² + 9y² - 8x - 18y - 19 = 0.\r\n" );
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document.write( "Ellipse since x² and y² have different coefficients with THE SAME SIGNS when\r\n" );
document.write( "on the same side of the equation.\r\n" );
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document.write( "20. Classify the conic section of the equation 9x² - 3 = 18x + 4y.\r\n" );
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document.write( "Parabola since there is only one term that has a variable squared.\r\n" );
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document.write( "Edwin

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