document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=751178>Question 751178</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many gallons of a 10% antifreeze solution and a 25 % Antifreeze solution must be mixed to make 3 gallons of a 20 % antifreeze solution? Solve with equations  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #457031 by </B><A HREF=/tutors/aboutme.mpl?userid=tommyt3rd><B>tommyt3rd(5050)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tommyt3rd><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tommyt3rd><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=457031\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How many gallons of a 10% antifreeze solution: 0.10x <BR>\n" );
document.write( "and a 25 % Antifreeze solution must be mixed: 0.25y <BR>\n" );
document.write( "to make 3 gallons of a 20 % antifreeze solution: (3)(0.20)=0.6\r<BR>\n" );
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document.write( "but x+y=3 (so y=3-x)\r<BR>\n" );
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document.write( "and we write\r<BR>\n" );
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document.write( "0.1x+0.25(3-x)=0.6\r<BR>\n" );
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document.write( "which gives us x=1 gallon\r<BR>\n" );
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document.write( ":) </SPAN>\n" );
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