document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=751163>Question 751163</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how much of an alloy that is 20% copper should be mixed with 500 ounces of an alloy that is 60% copper in order to get an alloy that is 30% copper<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #457025 by </B><A HREF=/tutors/aboutme.mpl?userid=tommyt3rd><B>tommyt3rd(5050)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tommyt3rd><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tommyt3rd><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=457025\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how much of an alloy that is 20% copper: 0.20x<BR>\n" );
document.write( "should be mixed with 500 ounces of an alloy that is 60% copper: 500(0.60)=300<BR>\n" );
document.write( "in order to get: = <BR>\n" );
document.write( "an alloy that is 30% copper: (x+500)(0.30)\r<BR>\n" );
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document.write( "putting them together:\r<BR>\n" );
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document.write( "0.2x+300=(x+500)(0.30)\r<BR>\n" );
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document.write( "which gives us x=1500 ounces\r<BR>\n" );
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document.write( ":) </SPAN>\n" );
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