document.write( "Question 751139: What is the perimeter and area of a 45°-45°-90° triangle with a hypotenuse length of 12 feet \n" ); document.write( "
Algebra.Com's Answer #457020 by Cromlix(4381)\"\" \"About 
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Using trigonometric ratios with
\n" ); document.write( "the right angle triangle.
\n" ); document.write( "Using cos = adjacent/hypotenuse
\n" ); document.write( " cos 45 = adjacent/12
\n" ); document.write( " Adjacent = 12*cos45 = 8.5 feet (1 decimal place)
\n" ); document.write( "Using sin = opposite/hypotenuse
\n" ); document.write( " sin45 = opposite/12
\n" ); document.write( " Opposite = 12*sin45 = 8.5 feet (1 decimal place)
\n" ); document.write( "
\n" ); document.write( " Perimeter =
\n" ); document.write( " 8.5 + 8.5 + 12 = 29 feet\r
\n" ); document.write( "\n" ); document.write( " Area of triangle = 1/2(b*h)
\n" ); document.write( " 1/2(8.5*8.5)
\n" ); document.write( " = 36.1 ft^2\r
\n" ); document.write( "\n" ); document.write( "Hope this helps
\n" ); document.write( ":-) \n" ); document.write( "
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