document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=751058>Question 751058</A>: <I><SPAN STYLE=\"word-break: break-all;\"> P varies jointly as m and u, and varies inversely as q. Given that p=4, m=3 and u=2 when q=1. Find the value of p when m=6, u=4 and q=8/5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #456971 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=456971\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P varies jointly as m and u and inversely as q<BR>\n" );
document.write( "p =kmu/q<BR>\n" );
document.write( "4 = k*3*2/1<BR>\n" );
document.write( "So k = 4/6 = 2/3\r<BR>\n" );
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document.write( "Formula => p = (2/3 * m * u)/q\r<BR>\n" );
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document.write( "           p = ( 2/3 * 6 * 4)/ 8/5<BR>\n" );
document.write( "           p = ( 16 ) / 8/5<BR>\n" );
document.write( "           p = (16 * 5)/8<BR>\n" );
document.write( "           p = 80 / 8<BR>\n" );
document.write( "           p = 10 \r<BR>\n" );
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document.write( "Hope this helps<BR>\n" );
document.write( ":-) </SPAN>\n" );
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