document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=751041>Question 751041</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a father is 61 and his son is 16 years old.in how many years will the father be twice as old as his son?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #456948 by </B><A HREF=/tutors/aboutme.mpl?userid=dkppathak><B>dkppathak(439)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dkppathak><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=dkppathak><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=456948\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> father is 61 yrs <BR>\n" );
document.write( "and son is 16 yrs <BR>\n" );
document.write( "as per conditions in how many years  father will be two times son age <BR>\n" );
document.write( "let x years after <BR>\n" );
document.write( "father =61+x<BR>\n" );
document.write( "son = 16+x<BR>\n" );
document.write( "61+x= 2(16+x)<BR>\n" );
document.write( "61+x =32+ 2x<BR>\n" );
document.write( "2x-x=61-32 =29<BR>\n" );
document.write( "yrs\r<BR>\n" );
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document.write( "answer after 29 yrs father will be twice of son age </SPAN>\n" );
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