document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=65176>Question 65176</A>: <I><SPAN STYLE=\"word-break: break-all;\"> D = C – s (for s)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #45687 by </B><A HREF=/tutors/aboutme.mpl?userid=mszlmb><B>mszlmb(115)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mszlmb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mszlmb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=45687\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=D=%28C-S%29%2FN ALIGN=MIDDLE  ALT=\"D=%28C-S%29%2FN\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "We want to get the S variable isolated (alone-ified) on one side of the equation.  First, we move the N.  To move the N, multiply both sides by it.  We do this because (C-S) is all divided by N, and the only way to subtract C so we can get S is to first multiply by their dividend, N.<br>\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=D=%28C-S%29%2FN ALIGN=MIDDLE  ALT=\"D=%28C-S%29%2FN\"   DISABLED_style= \"max-width:90%; height:auto;\" > so times N to both sides:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=D%2AN=%28C-S%29%2FN%2AN ALIGN=MIDDLE  ALT=\"D%2AN=%28C-S%29%2FN%2AN\"   DISABLED_style= \"max-width:90%; height:auto;\" >=><IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=DN=C-S ALIGN=MIDDLE  ALT=\"DN=C-S\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br>\r<BR>\n" );
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document.write( "See that, we've almost got S by itself!  Now to get rid of that pesky little 'C.'  Simply subtract both sides by C!<br>\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=DN-C=C-S-C ALIGN=MIDDLE  ALT=\"DN-C=C-S-C\"   DISABLED_style= \"max-width:90%; height:auto;\" >=><IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=DN-C=-S ALIGN=MIDDLE  ALT=\"DN-C=-S\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br>\r<BR>\n" );
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document.write( "We're <s>done!</s> almost finished: We have to rid ourself of the 'negative' sign!  We know that -S is the same as saying -1 times S [-1*S], so we multiply both sides by -1, since -1*-1=1:<br>\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28DN-C%29%2A-1=-S%2A-1 ALIGN=MIDDLE  ALT=\"%28DN-C%29%2A-1=-S%2A-1\"   DISABLED_style= \"max-width:90%; height:auto;\" >=><IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-%28DN-C%29=S ALIGN=MIDDLE  ALT=\"-%28DN-C%29=S\"   DISABLED_style= \"max-width:90%; height:auto;\" >  S is isolated!  We're <s>FINALLY DONE!!!</s> almost there..  We just have to distribute the '-' on the left:<br>\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-1%29DN-%28-1%29C=S ALIGN=MIDDLE  ALT=\"%28-1%29DN-%28-1%29C=S\"   DISABLED_style= \"max-width:90%; height:auto;\" >=><IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-DN-%28-C%29=S ALIGN=MIDDLE  ALT=\"-DN-%28-C%29=S\"   DISABLED_style= \"max-width:90%; height:auto;\" >  Recall that -(-x)= a positive x, so <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-DN%2BC=S ALIGN=MIDDLE  ALT=\"-DN%2BC=S\"   DISABLED_style= \"max-width:90%; height:auto;\" >  We can optionally arrange this to our liking,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=C-DN=S ALIGN=MIDDLE  ALT=\"C-DN=S\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  There, it's a simple as that!  Ask any questions you need to. </SPAN>\n" );
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