document.write( "Question 750884: The sum of the squares of two consecutive positive numbers is 41. What is the smaller number? \n" ); document.write( "
Algebra.Com's Answer #456862 by stanbon(75887)\"\" \"About 
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The sum of the squares of two consecutive positive numbers is 41. What is the smaller number?
\n" ); document.write( "-------
\n" ); document.write( "1st: x
\n" ); document.write( "2nd: x+1
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\n" ); document.write( "Equation:
\n" ); document.write( "x^2 + x^2+2x+1 = 41
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\n" ); document.write( "2x^2 + 2x - 40 = 0
\n" ); document.write( "x^2 + x -20 = 0
\n" ); document.write( "(x+5)(x-4) = 0
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\n" ); document.write( "Positive solution:
\n" ); document.write( "x = 4
\n" ); document.write( "x+1 = 5
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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