document.write( "Question 750883: The length of a rectangle is 8 inches greater than it' width. Find the width of a rectangle if it's area is 105 square feet. \n" ); document.write( "

Algebra.Com's Answer #456861 by jim_thompson5910(35256) $\"\"$ $\"About$

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A = LW\r
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\n" ); document.write( "\n" ); document.write( "105 = (x+8)(x)\r
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\n" ); document.write( "\n" ); document.write( "105 = x^2 + 8x\r
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\n" ); document.write( "\n" ); document.write( "x^2 + 8x = 105\r
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\n" ); document.write( "\n" ); document.write( "x^2 + 8x - 105 = 0\r
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\n" ); document.write( "\n" ); document.write( "(x + 15)(x - 7) = 0\r
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\n" ); document.write( "\n" ); document.write( "x + 15 = 0 or x - 7 = 0\r
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\n" ); document.write( "\n" ); document.write( "x = -15 or x = 7\r
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\n" ); document.write( "\n" ); document.write( "Toss out x = -15\r
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\n" ); document.write( "\n" ); document.write( "So the only solution that makes sense is x = 7\r
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\n" ); document.write( "\n" ); document.write( "Width: 7\r
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\n" ); document.write( "\n" ); document.write( "Length: 15 \n" ); document.write( "

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