document.write( "Question 65081This question is from textbook An Incremental Development
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\n" ); document.write( "\n" ); document.write( "Square root of x^2 - 3x - 6 - 3 = x - 2
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Algebra.Com's Answer #45684 by checkley71(8403)\"\" \"About 
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X^2-3X-6-3=X-2
\n" ); document.write( "X^2-3X-X-6-3+2=0
\n" ); document.write( "X^2-4X-7=0 USING THE QUADRATIC EQUATION X=(-B+-SQRT[B^2-4AC])/2A WE GET
\n" ); document.write( "X=(4+-SQRT[16-4*1*-7])/2*1
\n" ); document.write( "X=(4+-SQRT[16+28])/2
\n" ); document.write( "X=(4+-SQRT44)/2
\n" ); document.write( "X=(4+-6.63)/2
\n" ); document.write( "X=(4+6.63)/2
\n" ); document.write( "X=10.63/2
\n" ); document.write( "X=5.315 SOLUTION
\n" ); document.write( "X=(4-6.63)/2
\n" ); document.write( "X=-2.73/2
\n" ); document.write( "X=-1.315 SOLUTION
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