document.write( "Question 65081This question is from textbook An Incremental Development
\n" );
document.write( ": Solve\r
\n" );
document.write( "\n" );
document.write( "Square root of x^2 - 3x - 6 - 3 = x - 2 \n" );
document.write( "
Algebra.Com's Answer #45684 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! X^2-3X-6-3=X-2 \n" ); document.write( "X^2-3X-X-6-3+2=0 \n" ); document.write( "X^2-4X-7=0 USING THE QUADRATIC EQUATION X=(-B+-SQRT[B^2-4AC])/2A WE GET \n" ); document.write( "X=(4+-SQRT[16-4*1*-7])/2*1 \n" ); document.write( "X=(4+-SQRT[16+28])/2 \n" ); document.write( "X=(4+-SQRT44)/2 \n" ); document.write( "X=(4+-6.63)/2 \n" ); document.write( "X=(4+6.63)/2 \n" ); document.write( "X=10.63/2 \n" ); document.write( "X=5.315 SOLUTION \n" ); document.write( "X=(4-6.63)/2 \n" ); document.write( "X=-2.73/2 \n" ); document.write( "X=-1.315 SOLUTION \n" ); document.write( " |