document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=750843>Question 750843</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A line segment  GH has equation 3x+2y=15\r<BR>\n" );
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document.write( "(i) determine the gradient of GH\r<BR>\n" );
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document.write( "(ii) Another line segment, JK, is perpendicular to GH and passes through the point (4,1). Determine the equation of the line JK.If JK  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #456825 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=456825\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Sort the equation into y = mx + c<BR>\n" );
document.write( "3x + 2y = 15 => y = -3/2x + 15/2\r<BR>\n" );
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document.write( "i) Gradient of GH is -3/2.<BR>\n" );
document.write( "ii)If JK is perpendicular to GH<BR>\n" );
document.write( "then JK's gradient = 2/3\r<BR>\n" );
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document.write( " Lines that are perpendicular<BR>\n" );
document.write( "to other lines have gradients<BR>\n" );
document.write( "that multiply together to give<BR>\n" );
document.write( "-1. (m1xm2=-1)\r<BR>\n" );
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document.write( "Using y - b = m(x - a) and point (4,1)<BR>\n" );
document.write( "      y - 1 = 2/3(x - 1)<BR>\n" );
document.write( "          y = 2/3x - 2/3 + 1<BR>\n" );
document.write( "          y = 2/3x + 1/3<BR>\n" );
document.write( "         or by multiplying throughout<BR>\n" );
document.write( "         by 3<BR>\n" );
document.write( "          3y = 2x + 1\r<BR>\n" );
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document.write( "Hope this helps<BR>\n" );
document.write( ":-)\r<BR>\n" );
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document.write( " </SPAN>\n" );
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