document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=750800>Question 750800</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use algebra to solve the equation 4cos3x=-2/sin3x over the domain 0 greater than or equal to x and less than or equal to pi/3. Give exact answers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #456795 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=456795\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use algebra to solve the equation 4cos3x=-2/sin3x over the domain 0 greater than or equal to x and less than or equal to pi/3. Give exact answers.<BR>\n" );
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document.write( "0 &#8804; x &#8804; &#960;/3<BR>\n" );
document.write( "4cos3x=-2/sin3x<BR>\n" );
document.write( "4cos3xsin3x=-2<BR>\n" );
document.write( "divide by 2<BR>\n" );
document.write( "2cos3xsin3x=-1<BR>\n" );
document.write( "sin6x=-1<BR>\n" );
document.write( "6x=3&#960;/2<BR>\n" );
document.write( "x=3&#960;/12=&#960;/4 </SPAN>\n" );
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