document.write( "Question 750776: If a group of 6 people have an average age of 21, and each person is half the age of the next person, what are the ages of the 6 people \n" ); document.write( "

Algebra.Com's Answer #456777 by timvanswearingen(106) $\"\"$ $\"About$

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Let x be the age of the youngest of the 6 people. Then the rest of their ages are 2x, 4x, 8x, 16x, and 32x.\r
\n" ); document.write( "\n" ); document.write( "Since their average age is 21, 21*6=126. The sum of their ages is 126.\r
\n" ); document.write( "\n" ); document.write( " $\"x%2B2x%2B4x%2B8x%2B16x%2B32x=126\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"63x=126\"$ \r
\n" ); document.write( "\n" ); document.write( "Divide both sides by 63:\r
\n" ); document.write( "\n" ); document.write( " $\"x=2\"$ \r
\n" ); document.write( "\n" ); document.write( "So their ages are 2, 4, 8, 16, 32, and 64 \n" ); document.write( "

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