document.write( "Question 750622: Hi there I need to calculate out how far and high a boy named Jose throws in a ball in a football match, Y stands for the height in meters and X for the diatance in meters from where jose is standing.
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document.write( "How do I calculate Y=-0,04x^2+0,6x+2 \n" );
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Algebra.Com's Answer #456739 by nerdybill(7384) You can put this solution on YOUR website! Y=-0.04x^2+0.6x+2 \n" ); document.write( ". \n" ); document.write( "Maximum is at vertex: \n" ); document.write( "x-value of vertex is \"axis of symmetry\": \n" ); document.write( "x = -b/(2a) \n" ); document.write( "x = -0.6/(2*(-0.04)) \n" ); document.write( "x = -0.6/(-0.08) \n" ); document.write( "x = 0.6/(0.08) \n" ); document.write( "x = 7.5 \n" ); document.write( "Max height: \n" ); document.write( "Y=-0.04(7.5)^2+0.6(7.5)+2 \n" ); document.write( "Y= 4.25 meters (max height) \n" ); document.write( ". \n" ); document.write( "Max distance, we set Y to zero and solve for x: \n" ); document.write( "0=-0.04x^2+0.6x+2 \n" ); document.write( "0=0.04x^2-0.6x-2 \n" ); document.write( "0=0.02x^2-0.3x-1 \n" ); document.write( "applying the \"quadratic formula\" yields: \n" ); document.write( "x = {17.81, -2.81} \n" ); document.write( "throw out the negative solution (extraneous) leaving \n" ); document.write( "x = 17.81 meters (max distance) \n" ); document.write( ". \n" ); document.write( "details of \"quadratic formula\": \n" ); document.write( "
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