document.write( "Question 750544: A boat takes 8 hours to go 6 miles upstream and come back to the starting point. If the speed of the boat is 4 miles per hour in still water, what is the rate of the current? \n" ); document.write( "
Algebra.Com's Answer #456684 by stanbon(75887)\"\" \"About 
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A boat takes 8 hours to go 6 miles upstream and come back to the starting point. If the speed of the boat is 4 miles per hour in still water, what is the rate of the current?
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\n" ); document.write( "Upstream DATA:
\n" ); document.write( "time = x hrs ; distance = 6 miles ; rate = d/t = 6/x hrs
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\n" ); document.write( "Downstream DATA:
\n" ); document.write( "time = 8-x hrs ; distance = 6 miles ; rate = d/t = 6/(8-x)
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\n" ); document.write( "Equation:
\n" ); document.write( "Upstream Rate Eq::: 4-c = 6/x
\n" ); document.write( "Downstream Rt Eq::: 4+c = 6/(8-x)
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\n" ); document.write( "Add to solve for \"x\":
\n" ); document.write( "8 = (6/x)+(6/(8-x))
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\n" ); document.write( "8x(8-x) = 6(8-x) + 6x
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\n" ); document.write( "64x - 8x^2 = 48
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\n" ); document.write( "x^2 - 8x + 48 = 0
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\n" ); document.write( "No Real Number solution.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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