document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=65167>Question 65167</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0028241789/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Given the formula 1/Rr = 1/R1 + 1/R2 + R3 for the resistance of a circuit, determine the resistance R3 if Rr = 3 3/7 ohms, R1 = 6 ohms, and R2 = 3 ohms. The lowercase r and the 1, 2,and 3 with the capital R's are subscripts.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #45667 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=45667\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given the formula 1/Rr = 1/R1 + 1/R2 + R3 for the resistance of a circuit, determine the resistance R3 if Rr = 3 3/7 ohms, R1 = 6 ohms, and R2 = 3 ohms. <BR>\n" );
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document.write( "Rr=3 3/7 = 24/7 then 1/Rr=7/24<BR>\n" );
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document.write( "7/24 = 1/6 + 1/3 + R3<BR>\n" );
document.write( "Multiply thru by 24 to get:<BR>\n" );
document.write( "7 = 4 + 8 +24R3<BR>\n" );
document.write( "24R3=-5<BR>\n" );
document.write( "R3=-5/24<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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