document.write( "Question 750279: A truck can travel 140 miles in the same time it takes a car to travel 180 miles. If the trucks rate is 10 miles per hour slower than the cars, find the average rate for each.
\n" ); document.write( "The rate of the car is ____ miles per hour.
\n" ); document.write( "The rate of the truck is ____ miles per hour.
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Algebra.Com's Answer #456578 by ankor@dixie-net.com(22740)\"\" \"About 
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A truck can travel 140 miles in the same time it takes a car to travel 180 miles.
\n" ); document.write( " If the trucks rate is 10 miles per hour slower than the cars, find the average rate for each.
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\n" ); document.write( "let s = the speed of the truck
\n" ); document.write( "then
\n" ); document.write( "(s+10) = speed of the car
\n" ); document.write( ":
\n" ); document.write( "Write a time equation: time = dist/speed
\n" ); document.write( "\"140%2Fs\" + \"180%2F%28%28s%2B10%29%29\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "180s = 140(s+10)
\n" ); document.write( "180s = 140s + 1400
\n" ); document.write( "180s - 140s = 1400
\n" ); document.write( "40s = 1400
\n" ); document.write( "s = 1400/40
\n" ); document.write( "s = 35 mph is the speed of the truck
\n" ); document.write( ":
\n" ); document.write( "I'll let you find the speed of the car. Check your solutions by finding the
\n" ); document.write( "actual time of each, they should be equal\r
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