document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=750275>Question 750275</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangle is 700 yards.  Find the length and width of the rectangle if the length is 50 yards more than the width?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #456515 by </B><A HREF=/tutors/aboutme.mpl?userid=kibauu><B>kibauu(44)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kibauu><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=456515\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> length=l<BR>\n" );
document.write( "width=w\r<BR>\n" );
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document.write( "perimeter of rectangle=2(l+w)<BR>\n" );
document.write( "l=w+50\r<BR>\n" );
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document.write( "700 yards=2((w+50)+w)<BR>\n" );
document.write( "700=2.(2w+50)<BR>\n" );
document.write( "700=4w+100\r<BR>\n" );
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document.write( "that's easy now to find w and also l<BR>\n" );
document.write( "Cheers\r<BR>\n" );
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