document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=65154>Question 65154</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you solve this;<BR>\n" );
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document.write( "Four times the measure of the complement of angle B is 12 more than twice the differance between the measures of its supplement and complement.  Find the measures of angle B. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #45644 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=45644\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Four times the measure of the complement of angle B is 12 more than twice the differance between the measures of its supplement and complement. Find the measures of angle B.<BR>\n" );
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document.write( "The complement of angle B is (90-B)<BR>\n" );
document.write( "The supplement of angle B is (180-B)<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "4(90-B)=2((180-B)-(90-B))+12<BR>\n" );
document.write( "360-4B = 2(90)+12<BR>\n" );
document.write( "360-4B=192<BR>\n" );
document.write( "-4B=-168<BR>\n" );
document.write( "B=42 degrees<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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