document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=750120>Question 750120</A>: <I><SPAN STYLE=\"word-break: break-all;\"> x = log3/5 , y = log 5/4 and z = 2 log 3 square root of 2/2,find the value of :        x + y minus z<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #456425 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=456425\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = log 3/5 , y = log 5/4 and z = 2 log 3 square root of 2/2,find the value of : x + y minus z<BR>\n" );
document.write( "x+y-z=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%283%2F5%29%2Blog%285%2F4%29-2log%283sqrt%282%29%2F2%29=log%283%2F5%29%2Blog%285%2F4%29-log%28%283sqrt%282%29%2F2%29%29%5E2%0D%0A=log%283%2F5%2A5%2F4%2F%2818%2F4%29%29=log%2860%2F360%29=log%281%2F6%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >&#8776;-0.7782.. </SPAN>\n" );
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