document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=750171>Question 750171</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3.5 x 7^(4x-1)= 1000^(3-x)\r<BR>\n" );
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document.write( "find what x equals </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #456419 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=456419\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3.5 x 7^(4x-1)= 1000^(3-x)<BR>\n" );
document.write( "log(3.5) + (4x-1)*log(7) = (3-x)*log(1000) = (3-x)*3<BR>\n" );
document.write( "log(7) - log(2) + (4x-1)*log(7) = 9 - 3x<BR>\n" );
document.write( "log(7) - log(2) + 4x*log(7) - log(7) = 9 - 3x<BR>\n" );
document.write( "4xlog(7) + 3x = 9 + log(2)<BR>\n" );
document.write( "x*(4log(7) + 3) = log(2) + 9<BR>\n" );
document.write( "x = (log(2) + 9)/(4log(7) + 3)<BR>\n" );
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document.write( "x = (log(2) + log(10^9))/(log2401 + log(1000))<BR>\n" );
document.write( "x = log(2E9)/log(2401000)<BR>\n" );
document.write( "x =~ 1.457752088<BR>\n" );
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