document.write( "Question 750136: Internet Company A charges a $25 fee plus an additional $0.35 per hour. Internet Company B charges a $10 fee plus an additional $0.50 per hour. For what number of hours are the charges for both companies the same? \n" ); document.write( "
Algebra.Com's Answer #456390 by tommyt3rd(5050)\"\" \"About 
You can put this solution on YOUR website!
First we write their total charges as equations. Then we solve for t - the number of hours when both charges are equal\r
\n" ); document.write( "\n" ); document.write( "\"A=0.35t%2B25\"\r
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\n" ); document.write( "\n" ); document.write( "\"B=0.50t%2B10\"\r
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\n" ); document.write( "\n" ); document.write( "When they charge the same A=B and we can write\r
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\n" ); document.write( "\n" ); document.write( "\"0.35t%2B25=0.50t%2B10\"\r
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\n" ); document.write( "\n" ); document.write( "\"25-10=0.5t-0.35t\"\r
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\n" ); document.write( "\n" ); document.write( "\"15=0.15t\"\r
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\n" ); document.write( "\n" ); document.write( "so t=100 hours\r
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