document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=750133>Question 750133</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Train A leaves a station traveling at 80 kilometers per hour. Four hours later, train B leaves the same station traveling in the same direction at 90 kilometers per hour. How long does it take train B to catch up to trian A? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #456379 by </B><A HREF=/tutors/aboutme.mpl?userid=sachi><B>sachi(548)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sachi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sachi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=456379\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let train B catches A after x hrs<BR>\n" );
document.write( "in x hrs b travels 90x km<BR>\n" );
document.write( "& in x+4 hrs A travels 80(x+4) as A left 4 hrs before<BR>\n" );
document.write( "now both distances are same<BR>\n" );
document.write( "so 90x=80(x+4)=80x+320<BR>\n" );
document.write( "or 10x=320<BR>\n" );
document.write( "or x=32 hrs  </SPAN>\n" );
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