document.write( "Question 750129: A motorboat can go 12 miles downstream on a river in 20 minutes. It takes 30 minutes for this boat to go back upstream the same 12 miles. Whats the speed of the boat in still water? \n" ); document.write( "
Algebra.Com's Answer #456368 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A motorboat can go 12 miles downstream on a river in 20 minutes. \n" ); document.write( "It takes 30 minutes for this boat to go back upstream the same 12 miles. \n" ); document.write( "Whats the speed of the boat in still water? \n" ); document.write( "--------- \n" ); document.write( "Downstream DATA: \n" ); document.write( "dist = 12 miles ; time = 1/3 hr ; rate = d/t = 36 mph \n" ); document.write( "---------------------- \n" ); document.write( "Upstream DATA: \n" ); document.write( "dist = 12 miles ; time = 1/2 hr ; rate = d/t = 24 mph \n" ); document.write( "--------------------- \n" ); document.write( "Equation: \n" ); document.write( "Downstream: b + c = 36 mph \n" ); document.write( "Upsteam ::: b - c = 24 mph \n" ); document.write( "------------------------------ \n" ); document.write( "Solve for \"b\": \n" ); document.write( "2b = 60 mph \n" ); document.write( "b = 30 mph (speed of the boat in quiet water) \n" ); document.write( "------ \n" ); document.write( "Solve for \"c\": \n" ); document.write( "2C = 12 mph \n" ); document.write( "c = 6 mph (speed of the current) \n" ); document.write( "================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============== \n" ); document.write( " \n" ); document.write( " |