document.write( "Question 750065: Miami and Pittsburg are 1000 miles apart. A plane flew into a 50mph headwind from miami to pittsburg. on the return flight the 50mph wind became a tailwind. The lane was in the air a total of 4.5 hrs. for the roundtrip. what would have been the planes average speed without the wind? \n" ); document.write( "
Algebra.Com's Answer #456358 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Miami and Pittsburg are 1000 miles apart. A plane flew into a 50mph headwind from miami to pittsburg. on the return flight the 50mph wind became a tailwind. The lane was in the air a total of 4.5 hrs. for the roundtrip. what would have been the planes average speed without the wind? \n" ); document.write( "------------ \n" ); document.write( "p = plane's airspeed \n" ); document.write( "---- \n" ); document.write( "1000/(p - 50) + 1000/(p + 50) = 4.5 \n" ); document.write( "----- \n" ); document.write( "1000*(2p) = 4.5*(p^2 - 2500) \n" ); document.write( "4000p = 9p^2 - 22500 \n" ); document.write( "9p^2 - 4000p - 22500 = 0 \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "============ \n" ); document.write( "Ignore the negative solution, \n" ); document.write( "p = 450 mi/hr \n" ); document.write( "---------- \n" ); document.write( "with no wind, the avg = 450 mi/hr \n" ); document.write( " \n" ); document.write( " |