document.write( "Question 750048: Please Help\r
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\n" ); document.write( " Solve the following equation for x, if 0 ≤ x ≤ 2π \r
\n" ); document.write( "\n" ); document.write( "√2cosx=-1
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Algebra.Com's Answer #456297 by tommyt3rd(5050)\"\" \"About 
You can put this solution on YOUR website!
√2cosx=-1\r
\n" ); document.write( "\n" ); document.write( "\"cosx=-1%2Fsqrt%282%29=-sqrt%282%2F2%29\"\r
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\n" ); document.write( "\n" ); document.write( "The principle value is \"pi%2F4\"\r
\n" ); document.write( "\n" ); document.write( "but our angle is negative so that puts our angle in quadrants II and III, meaning our solutions are\r
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\n" ); document.write( "\n" ); document.write( "\"%283pi%29%2F4\" or \"%285pi%29%2F4\"
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