document.write( "Question 749959: In the absence of air resistance, the trajectory of a cannon ball fired from ground level at 1200 feet per second and at an angle of 45o can be approximated as\r
\n" ); document.write( "\n" ); document.write( "y=x-1/45,000x^2\r
\n" ); document.write( "\n" ); document.write( "where y is the height above the ground and x is the distance from the cannon.\r
\n" ); document.write( "\n" ); document.write( "A. Find the vertex of the parabola described by this equation\r
\n" ); document.write( "\n" ); document.write( "B. What is the maximum height of the cannon ball?\r
\n" ); document.write( "\n" ); document.write( "C. What is the range of the cannon ball (the range is the horizontal distance to the point of impact at ground level)?\r
\n" ); document.write( "\n" ); document.write( "I'm a bit confused on how to find all these! Any help is appreciated thanks!
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Algebra.Com's Answer #456273 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
In the absence of air resistance, the trajectory of a cannon ball fired from ground level at 1200 feet per second and at an angle of 45 degrees can be approximated as
\n" ); document.write( "y=x-\"1%2F45000\"x^2
\n" ); document.write( "WRite this in the standard form: y = ax^2 + bx + c
\n" ); document.write( "y = \"-1%2F45000\"x^2 + x
\n" ); document.write( "where y is the height above the ground and x is the distance from the cannon.
\n" ); document.write( "A. Find the vertex of the parabola described by this equation
\n" ); document.write( "Find the axis of symmetry which is x = -b/(2a)
\n" ); document.write( "x = \"%28-1%29%2F%282%2A%28-1%2F45000%29%29\" = \"%28-1%29%2F%28%28-2%2F45000%29%29\" = +22500
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\n" ); document.write( "B. What is the maximum height of the cannon ball?
\n" ); document.write( "Replace x with 22500 in the original equation, find y
\n" ); document.write( "y = \"-1%2F45000\"22500^2 + 22500
\n" ); document.write( "y = +11250 ft max height
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\n" ); document.write( "C. What is the range of the cannon ball (the range is the horizontal distance to the point of impact at ground level)?
\n" ); document.write( "At impact, y = 0, occurs twice the value of the axis of symmetry
\n" ); document.write( "x = 2(22500) = 45000 ft
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\n" ); document.write( "Graphically
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-10000%2C+50000%2C+-2000%2C+15000%2C+%28-1%2F45000%29x%5E2%2Bx%29+\"
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