document.write( "Question 749902: Randy rode out of town on the bus at an average speed of 24 miles per hour and walked back at an average speed of 3 mile sper hour. How far did he go if he was gone for six hours? (Having trouble setting it up) \n" ); document.write( "
Algebra.Com's Answer #456199 by timvanswearingen(106)\"\" \"About 
You can put this solution on YOUR website!
Use distance=rate*time. You can set up a couple equations for d and set them equal to find t. Then you'll plug back in to find d.\r
\n" ); document.write( "\n" ); document.write( "\"d=24mi%2Fh%2At\"\r
\n" ); document.write( "\n" ); document.write( "The time t spent on the bus will be subtracted from 6 (since the total time was 6 hours). This will give the time spent walking:\r
\n" ); document.write( "\n" ); document.write( "\"d=3mi%2Fh%2A%286-t%29\"\r
\n" ); document.write( "\n" ); document.write( "Now set the two equal and solve for t, then plug the t back into one of the previous equations to find the distance:\r
\n" ); document.write( "\n" ); document.write( "\"24mi%2Fh%2At=3mi%2Fh%2A%286-t%29\"
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