document.write( "Question 749902: Randy rode out of town on the bus at an average speed of 24 miles per hour and walked back at an average speed of 3 mile sper hour. How far did he go if he was gone for six hours? (Having trouble setting it up) \n" ); document.write( "
Algebra.Com's Answer #456199 by timvanswearingen(106) You can put this solution on YOUR website! Use distance=rate*time. You can set up a couple equations for d and set them equal to find t. Then you'll plug back in to find d.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The time t spent on the bus will be subtracted from 6 (since the total time was 6 hours). This will give the time spent walking:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now set the two equal and solve for t, then plug the t back into one of the previous equations to find the distance:\r \n" ); document.write( "\n" ); document.write( " |